The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id.
+—-+——-+——–+———–+ | Id | Name | Salary | ManagerId | +—-+——-+——–+———–+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Max | 90000 | NULL | +—-+——-+——–+———–+
Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager.
+———-+ | Employee | +———-+ | Joe | +———-+
Link: https://leetcode.com/problems/employees-earning-more-than-their-managers/
Solution #
select A.Name as Employee from Employee A, Employee B where A.ManagerId = B.Id and A.Salary > B.Salary;